Q:

Solve 2x2 βˆ’ 8x = βˆ’7. (2 points)A. negative 2 plus or minus square root of 2B. negative 2 plus or minus 2 square root of 2C. quantity of 2 plus or minus square root of 2 all over 2D. 2 plus or minus square root of 2 end root over 2If you do not know the answer or are not sure about your answer DO NOT ANSWER!!!!!!If you give the right answer I will give you Brainlyest, Rate you five star and give you thanks

Accepted Solution

A:
Answer:D. 2 plus or minus square root of 2 end root over 2Step-by-step explanation:Given equation,[tex]2x^2 - 8x = -7[/tex][tex]\implies 2x^2 - 8x + 7=0[/tex]By the quadratic formula,[tex]x=\frac{-(-8)\pm \sqrt{(-8)^2 -4\times 2\times 7}}{2\times 2}[/tex][tex]x=\frac{8\pm \sqrt{64 - 56}}{4}[/tex][tex]x=\frac{8\pm \sqrt{8}}{4}[/tex][tex]x=\frac{8\pm 2\sqrt{2}}{4}[/tex][tex]x=2\pm \frac{\sqrt{2}}{2}[/tex]= 2 plus or minus square root of 2 end root over 2OPTION D Is correct.